MOSCOW, July 15 (RIA Novosti) - Russia will pay 24,310,000 roubles (1 dollar equals 29 roubles) for 2004 to the IAEA technical assistance and cooperation fund. Prime Minister Mikhail Fradkov has inked the instruction approving the corresponding proposal of the Federal Nuclear Energy Agency, coordinated with the foreign and finance ministries.
"Towards the fulfilment of obligations of the Russian Federation ensuing from its membership in the International Atomic Energy Agency, the proposal on the payment of the due, in the national currency, of the Russian Federation to the IAEA Technical Assistance and Cooperation Fund for 2004 shall be accepted", reads the communique posted on the government's official web site.
The government has also approved the allocation of 7,050,000 roubles this year for financing the national programme of scientific-technical support for IAEA safeguards.
The communique notes that the Federal Nuclear Energy Agency has been instructed to ensure the financing of events from the resources provided for in the 2004 federal budget.
